Question

y(2y-3)(y-8)=0 como resolver?

Answer 1

(2y-3)(y-8)=34.

2y² -16y -3y² + 24 =34

2y² -3y² -16y +24 -34-y² -16y-10=0

a=(-1) b) (-16) c) (-10)

delta= b²-4.a.c

delta= (-16)² -4.(-1).(-10)

delta= 256-40

delta= 216

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