Question

Y= 2x²+5/ 3x-4 derive​

Answer 1

Derivada do quociente

$\boxed{\boxed{\boxed{\boxed{\mathsf{(\dfrac{u} {v})'=\dfrac{u'.v-u.v'}{v^2}}}}}}$

$\mathsf{y=\dfrac{2x^2+5}{3x-4}}\\\mathsf{\dfrac{dy}{dx}=\dfrac{4x(3x-4)-(2x^2+5).3}{(3x-4)^2}}\\\mathsf{\dfrac{dy}{dx}=\dfrac{12x^2-16x-6x^2-15}{(3x-4)^2}}$

$\large\boxed{\boxed{\boxed{\boxed{\mathsf{\dfrac{dy}{dx}=\dfrac{6x^2-16x-15}{(3x-4)^2}}}}}}$