Question

Y: 2-² + 2² - 2-¹/2-² - 2-¹

Answer 1

$y= \frac{2^-^2+2^2-2^-^1}{2^-^2-2^-^1} Resolvendo o numerador: [tex] \frac{1}{2^2}+2^2- \frac{1}{2}= \frac{1}{4}+4- \frac{1}{2}= \frac{17}{4} - \frac{1}{2}= \frac{17-2}{4}= \frac{15}{4}$

Resolvendo o denominador:
$\frac{1}{2^2}- \frac{1}{2}= \frac{1}{4}- \frac{1}{2}= \frac{1-2}{4}=- \frac{1}{4}$

Ficou assim:
$\frac{ \frac{15}{4} }{- \frac{1}{4} }= \frac{15}{4}:(- \frac{1}{4})= \frac{15}{4}*(-4)=$

$\boxed{-15}$