Question

X³.(x‐3)=
(2x+2)³=
(2x+2)³=
(8‐a)²=
(X+9).(x+2)=
(X+2).(3x²+y)=
(X‐3y)³
Rápido tenho 15 min pra fazer

Answer 1

Olá

x³.(x‐3)= x⁴ - 3x³

(2x+2)³= (4x² + 8x + 4).(2x + 2) = 8x³ + 8x² + 16x² + 16x + 8x + 8 = 8x³ + 24x² + 24x + 8

(2x+2)³=  (4x² + 8x + 4).(2x + 2) = 8x³ + 8x² + 16x² + 16x + 8x + 8 = 8x³ + 24x² + 24x + 8

(8‐a)²= 64 - 16a + a²

(x+9).(x+2)= x² + 2x + 9x + 18 = x² + 11x + 8

(x+2).(3x²+y)= 3x³ + xy + 6x² + 2y = 3x³ + 6x² + xy + y

(x‐3y)³= (x² - 6xy + 9y²).(x - 3y) = x³ - 3x²y - 6x²y + 18xy² + 9xy² - 27y³ = x³ - 9x²y + 27xy² - 27y³

Answer 2

Explicação passo-a-passo:

${x}^{3}(x - 3) = {x}^{4} - 3x \\ \\ (2x + 2).(2x + 2) = \\ {4x}^{2} + 4x + 4x + 4 = \\ ({4x}^{2} + 8x + 4) .(2x + 2) = \\ {8x}^{3} + {8x}^{2} + {16}^{2} + 16x + 8x + 8 = \\ {8x}^{3} + {24x}^{2} + 8x + 8 \\ \\ (8 - a).(8 - a) = \ \ 64 - 8a - 8a + {a}^{2} = \\ {a}^{2} - 16a + 64 \\ \\ (x + 9).(x + 2) = \\ {x}^{2} + 2x + 9x + 18 = \\ {x}^{2} + 11x + 18 \\ \\ (x + 2).( {3x}^{2} + y) = \\ {3x}^{3} + xy + {6x}^{2} + 2y = \\ {3x}^{3} + {6x}^{2} + 2y + xy \\ \\ {(x - 3y)}^{3} = \\ (x - 3y).(x - 3y) = \\ {x}^{2} + 3yx - 3yx + {9y}^{2} = \\ ({x}^{2} + {9y}^{2}).(x - 3y) = \\ {x}^{3} - 3 {x}^{2} y + {9y}^{2} x - {27y}^{3} \\ {x}^{3} - {27y}^{3} - 3 {x}^{2} y + {9y}^{2} x$