Question

-X²13x-40=0 alguém pode mim ajudar pfvr?

Answer 1

$-x^2-13x-40=0$

Coeficientes: a= -1, b = -13 e c = -40

$\Delta=b^2-4ac\\\Delta=(-13)^2-4\cdot(-1)\cdot(-40)\\\Delta=169-160\\\Delta=9$

$x=\frac{-b+-\sqrt{\Delta}}{2a}\\\\x=\frac{-(-13)+-\sqrt{9}}{2\cdot(-1)}\\\\x=\frac{13+-3}{-2}\\\\x_1=\frac{13+3}{-2}=\frac{16}{-2}=-8\\\\x_2=\frac{13-3}{-2}=\frac{10}{-2}=-5$



Espero ter ajudado.
Bons estudos! :)