Question

x²+y-4 = de novo desculpa
​

Answer 1

x²+y-4

$x^2+y-4=0:\quad \mathrm{Parabola\:com\:vertice\:em}\:\left(h,\:k\right)=\left(0,\:4\right),\:\mathrm{e\:distancia\:focal}\:|p|=\frac{1}{4}$

$4p\left(y-k\right)=\left(x-h\right)^2\:\mathrm{\:e\:a\:equacao\:geral\:da\:parabola\:de\:eixo\:vertical,\:com\:vertice\:em\:}$

$:\left(h,\:k\right),\:\mathrm{e\:distância\:focal}\:|p|$

$\left(h,\:k\right)=\left(0,\:4\right),\:p=-\frac{1}{4}$