Question

x2-x-6=0 econtrar o valor de delta

Answer 1

X2-x-6=0 econtrar o valor de delta

X2-x-6=0 

Δ = b² - 4ac

Δ= (-1)² - 4.1.(-6)==> 1+24==> 25

Answer 2

$x^{2} - x - 6 = 0$

$\Delta = b^2 -4*a*c$

a = 1
b = -1
c = -6

===

Δ = b²−4ac

Δ = (−1)²−4⋅(1)⋅(−6)Δ = 1+24Δ = 25