Question

x²-x+4=0 socorrooooo!

Answer 1

$x^{2} -x+4=0 \Delta= b^{2} -4.a.c/2.a \Delta= (-1)^{2}-4.1.4=\Delta=1-16=15[tex] x1=-+(-1) \sqrt{15} /2 x^{2} =-+(-1) \sqrt{15} /2$ [/tex]