Question

x²=x+12
preciso urgentee

Answer 1

$x^{2} = x+12$
$x^{2} - x -12= 0$ (passa tudo para mesmo lado com sinal oposto)
Aplica Baskara. 
Δ=b²-4. a.c 
Δ= 1²-4(1)(-12)
Δ=1+48
Δ=49
 
x=$\frac{1+- \sqrt{49} }{2.a}$
$x'= \frac{1+7}{2} = \frac{8}{2} =4$
$x''= \frac{-6}{2} = -3$
    


Raizes$\left \{ {{x'=4} \atop {x''=-3}} \right.$

Answer 2

x² = x + 12

x² - x - 12 = 0


delta = b² - 4.a.c


a = 1
b = -1
c = -12


delta = (-1)² - 4.1.(-12)
delta = 1 + 48
delta = 49


x = -b ± √delta/2.a

x = -(-1) ± √49/2

x = 1 ± 7/2

x = 1 - 7/2 = -6/2 = -3

x = 1 + 7/2 = 8/2 = 4


s={ -3, 4 }




☆Espero ter ajudado!