Question

x²-x-12=0 me ajudem por favor​

Answer 1

x²-x-12=0

(-b±($\sqrt {b²-4.a.c}$))/2.a

(-(-1)±($\sqrt {(-1)²-4.1.(-12)}$))/2.1

(1±($\sqrt {1-(-48)}$))/2

(1±($\sqrt {1+48)}$))/2

(1±($\sqrt {49}$))/2

1±7/2

x1=(1+7)/2 = 8/2 = 4

x2=(1-7)/2 = -6/2 = -3