Question

-x2+x+12=0 fórmula de baskhara e delta​

Answer 1

Resposta:

Explicação passo-a-passo:

$-x^{2}+x+12=0\\\\\Delta=(b)^{2}-4(a)(c)=(1)^{2}-4(-1)(12)=1-(-48)=49\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(1)-\sqrt{49}}{2(-1)}=\frac{-1-7}{-2}=\frac{-8}{-2}=4\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(1)+\sqrt{49}}{2(-1)}=\frac{-1+7}{-2}=\frac{6}{-2}=-3$

Answer 2

Baskhara= -b²+-√∆
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2.a
∆= b²-4.a.c