Question

x2 + 9x + 14 = 0 FORMULA DE BHASKARA ALGUEM RESOLVE ?

Answer 1

a = 1 b= 9 c = 14

Delta = b2 - 4ac

9 ao quadrado - 4 x 1 x 14

81 - 56

25

Delta = 25

BHASKARA = -b +- raiz de DEALTA / 2a

-9 +- raiz de 25 / 2

-9 +- 5 / 2

x1 = -9 + 5/2 e X2= -9 - 5/2

x1= -2   e    x2= -7

Answer 2

$x^{2} + 9x + 14 = 0 \\ delta = b^{2} - 4ac \\ delta = 81 - 56 \\ delta = 25 \\ x = \frac{-b +ou- \sqrt{delta}}{2a} \\ x' = \frac{-9 + 5}{2} \\ x' = \frac{-4}{2} \\ x' = -2 \\ x''= \frac{-9 -5}{2} \\ x'' = \frac{-14}{2} \\ x'' = -7$
S = {-7;-2}