Question

x2+9×+8=0 (R:-1 e -8)

Answer 1

Oi Thaiane

x² + 9x + 8 = 0

a= 1

b=9

c=8

Calculando delta

Δ = b² - 4.a.c

Δ = 9² - 4.1.8

Δ = 81 - 32

Δ = 49

Aplicando Bhaskara

x = - b +- √49/2.a

x' = - 9 + √49/2.1

x' = - 9 + 7/2

x' = - 2/2

x' = - 1

x" = - b - √49/2.1

x" = - 9 - 7/2

x" = - 16/2

x" = - 8

S={x' = - 1 e x" = - 8}

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