Question

x2-8x+7=0 com a fórmula de Bhaskara

Answer 1

x² - 8x + 7 = 0

Δ = b² - 4ac
Δ = 36

x' = 7
x" = 1

S = {1, 7}

Answer 2

 x² - 8x + 7 =0

a=1
b=-8
c=7

Δ=b²-4ac
Δ=(-8)²-4(1)(7)
Δ=64-28
Δ=36

$x= \frac{-b\pm \sqrt{\Delta} }{2a} =~~ \frac{-(-8)\pm \sqrt{36} }{2} =~~ \frac{8\pm6}{2} \\ \\ x'= \frac{8+6}{2} = \frac{14}{2} =7 \\ \\ x"= \frac{8-6}{2} = \frac{2}{2} =1 \\ \\ S=\{1,7\}$