Question

X²-8x+12=0
.........
​

Answer 1

$x_{1,\:2}=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:12}}{2\cdot \:1}\\x_{1,\:2}=\frac{-\left(-8\right)\pm \:4}{2\cdot \:1}\\x_1=\frac{-\left(-8\right)+4}{2\cdot \:1},\:x_2=\frac{-\left(-8\right)-4}{2\cdot \:1}\\x=6,\:x=2$

Answer 2

Resposta:

Explicação passo a passo:

X²-8x+12=0

a = 1; b = - 8; c = 12

/\= b^2 - 4ac

/\= (-8)^2 - 4.1.12

/\=64 - 48

/\= 16

X = [-(-8)+/- \/16]/2.1

X = (8 +/- 4)/2

X ' = (8+4)/2 = 12/2= 6

X" = (8-4)/2= 4/2 = 2

R.: V = {2;6}