Question

x²+8x=0 com a formula de bhaskara

Answer 1

Olá, veja os cálculos abaixo.

x²+ 8x = 0

Δ = (b)² -4.a.c

Δ = (8)² -4.1.0

Δ = 64

x = -b ⁺⁻√Δ ÷ 2.a

x = -8 ⁺⁻√64 ÷ 2.1

x = -8 ⁺⁻ 8 ÷ 2

x1 = -8 + 8 ÷ 2 ∴ x1 = 0

x2 = -8 - 8 ÷ 2 ∴ x2 = -8

S = {-8, 0}