Question

x2+7x+12=o (x ao quadrado)

Answer 1

x²+7x+12 = 0
/\ = 7²-4.1.12
/\ = 49-48
/\ = 1
x = (-7+/-√1)/2.1
x = (-7+/-1)/2
x' = (-7+1)/2 = -6/2 = -3
x" = (-7-1)/2 = -8/2 = -4
S: {-3; -4}

Answer 2

x² + 7x + 12 = 0

a = 1
b = 7
c = 12

Δ = b² - 4ac
Δ = 7² - 4(1)(12)
Δ = 49 - 48
Δ = 1

x = $\frac{-b \frac{+}{-} \sqrt{b^2-4ac} }{2a}$

x = $\frac{-7 \frac{+}{-} \sqrt{1} }{2.1}$

x = $\frac{-7 \frac{+}{-}1 }{2}$

x' = $\frac{-7-1}{2}$

x' = $\frac{-8}{2}$

x' = -4

x" = $\frac{-7+1}{2}$

x" = $\frac{-6}{2}$

x" = -3

S = {-3,-4}