Question

x2-7x+12=0
como resolver passo a passo?

Answer 1

x² - 7x + 12 = 0
a  = 1; b= - 7 ; c = 12

Δ = b² - 4ac
Δ = (-7)² - 4.1.12
Δ = 49 - 48
Δ = 1

x = - b +/-√Δ =  - ( - 7) +/- √1 
          2a               2.1

x = 7 + 1 = 8/2 = 4
       2

x = 7 - 1 = 6/2 = 3
        2

Resposta.: x = 4 e x = 3

Answer 2

x² -7x+12=0
a=1
b=-7
c=12

Δ=b²-4ac
Δ=(-7)²-4(1)(12)
Δ=49 -48
Δ=1

x=(-b±√Δ)/2a

x=[-(-7)±√1)/2a

x=(7±1)/2

x'=(7+1)/2=8/2=4

x=(7-1)/2=6/2=3

as raizes são 4 e 3