Question

x2-7x+10=0 resolução​

Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}-7x+10=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=1{;}~b=-7~e~c=10\\\\\Delta=(b)^{2}-4(a)(c)=(-7)^{2}-4(1)(10)=49-(40)=9\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-7)-\sqrt{9}}{2(1)}=\frac{7-3}{2}=\frac{4}{2}=2\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-7)+\sqrt{9}}{2(1)}=\frac{7+3}{2}=\frac{10}{2}=5\\\\S=\{2,~5\}$

Answer 2

Explicação passo-a-passo:

x² - 7x + 10 = 0

Δ = (-7)² - 4.1.10

Δ = 49 - 40

Δ = 9

x = (7 ± √3)/2.1 = (7 ± 3)/2

• x' = (7 + 3)/2 = 10/2 = 5

• x" = (7 - 3)/2 = 4/2 = 2