Question

X²-6x+8=0 utilizando formulá de Báskara

Answer 1

x² - 6x + 8 = 0


delta = b² - 4.a.c

a = 1
b = -6
c = 8

delta = (-6)² - 4.1.8
delta = 36 - 32
delta = 4

x = -b ± √delta/2.a


x = -(-6) ± √4/2.1

x = 6 ± 2/2

x = 6 - 2/2 = 4/2 = 2

x = 6 + 2/2 = 8/2 = 4

s={ 2, 4 }



☆Espero ter ajudado!