Question

X²+6x+8=0 usando a fórmula de bhaskara

Answer 1

Boa Noite !!!

$a = 1\\b = 6\\c = 8$

Δ = $b^{2} -4.a.c$

Δ = $36 - 4.1.8$

Δ = 36 - 32

Δ = 4

$\frac{-b-+\sqrt{4} }{2.a}$

$\frac{-6-+2}{2}$

x¹ = $\frac{-8}{2}$

x¹ = -4

x" = $\frac{-4}{2}$

x" = -2

Espero ter ajudado :-)

Att: LDC