Question

-x2-6x-8=0 formula de bhaskara

Answer 1

-x² - 6x - 8 = 0

x² + 6x + 8 = 0

∆ = 6² - 4.1.8

∆ = 36 - 32

∆ = 4

$x = \frac{ - 6 + - \sqrt{4} }{2 \times 1}$

$x = \frac{ - 6 + - 2}{2}$

$x_{1} = \frac{ - 6 - 2}{2} \\ x_{2} = \frac{ - 6 + 2}{2}$

$x_{1} = - 4 \\ x_{2} = - 2$

Answer 2

Resposta:

-x²-6x-8=0

a)-1

b)-6

c)-8

∆=b²-4ac

∆=(-6).-4.-1.-8

∆=36-32

∆=4

X=b-+√∆

2a

X=(-6)-+√4

2.1

X=-6-+2

2

X¹=-6-2=

2

X¹=-8=X¹=-4

2

X²=-6+2=

2

X²=-4=X²=-2

2