Question

-x²+6x-5=0


preciso de ajuda

Answer 1

$- x {}^{2} + 6x - 5 = 0 \\ x {}^{2} - 6x + 5 = 0 \\ x { }^{2} - x - 5x + 5 = 0 \\ x \times (x - 1) - 5(x - 1) = 0 \\ (x - 1) \times (x - 5) = 0 \\ x - 1 = 0 \\ x - 5 = 0 \\ x1 = 1 \\ x2 = 5$