Question

-x² + 6x - 5 = 0 fórmula resolutiva x¹ e x ²​

Answer 1

Resposta:

$-x^2+6x-5=0$

$x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\left(-1\right)\left(-5\right)}}{2\left(-1\right)}$

$x_1=\frac{-6+4}{2\left(-1\right)},\:x_2=\frac{-6-4}{2\left(-1\right)}$

$x=1,\:x=5$