Question

x²+6x+3=0
Conta montada por favor ?

Answer 1

Δ = 6² - 4 . 1 . 3
Δ = 36 - 12
Δ = 24

x' =  ( - 6 + 2$\sqrt{6}$ ) /2  
x' = -3 + 2$\sqrt{6}$
x'' =  -3 - 2$\sqrt{6}$ 

Answer 2

$x^{2} + 6x + 3 = 0$

Resolvendo por Bháskara:

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a=1, b=6, c=3

Δ=b²−4ac
Δ=(6)2−4*(1)*(3)
Δ=36−12
Δ=24

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a}$


$x = \dfrac{-6 \pm \sqrt{\24}}{2*1} \\ \\ \\ x = \dfrac{-6 \pm 2\sqrt{6}}{2} \\ \\ \\ x' = \dfrac{-6 + 2\sqrt{6}}{2} \\ \\ \\x' = -3 + \sqrt{6} \\ \\ \\ x'' = \dfrac{-6 + 2\sqrt{6}}{2} \\ \\ \\ x'' = -3 -\sqrt{6}$

==========

S = { $-3 + \sqrt{6}, \ \ -3 -\sqrt{6}$ }