Question

x2 +6x +2 = 0 pela fórmula de bhaskara

Answer 1

$x^2+6x+2=0 \\ \\ a=1 \\ b=6 \\ c=2 \\ \\ \Delta=b^2-4ac \\ \Delta=6^2-4(1)(2) \\ \Delta=36-8 \\ \Delta=28 \\ \sqrt{\Delta} = \sqrt{28} \\ \sqrt{\Delta} = \sqrt{2^4.7} \\ \sqrt{\Delta} =4 \sqrt{7} \\ \\ x= \frac{-b\pm \sqrt{\Delta} }{2a} = \frac{-6\pm2 \sqrt{7} }{2} = \frac{\not2(-3\pm \sqrt{7} )}{\not2} \\ \\ x'=-3+ \sqrt{7} \\ \\ x"=-3- \sqrt{7}$