Question

x2 + 6x 2 = 0 feito pela fórmula de bhaskara preciso de ajuda

Answer 1

x^{2}+6x+2=0
Δ=6²-4(1)(2)
Δ=36-8
Δ=28

x=-b+-√Δ
         2a
x1=-6+2√7=-4√7=-2√7=-5,28
         2            2
x2=-6-2√7=-8√7=-4√7=-10,56
          2          2

Answer 2

$x^{2} +6x+2=0 \\ \\ a=1 \\ b=6 \\ c=2 \\ \\ \Delta=b^2-4ac \\ \Delta=6^2-4(1)(2) \\ \Delta=36-8 \\ \Delta=28 \\ \\ x= \frac{-b\pm \sqrt{\Delta} }{2a} =\frac{-6\pm \sqrt{28} }{2} = \frac{-6\pm \sqrt{2^2.7} }{2} = \frac{-6\pm2 \sqrt{7} }{2} = \frac{\not2(-3\pm \sqrt{7}) }{\not2} = \\ \\ x'=-3+ \sqrt{7} \\ \\ x"=-3- \sqrt{7}$