Question

x²-6x-16=0 determine o valor de x1 e x2

Answer 1

a= 1
b= -6
c= -16

∆= b^2-4ac
∆= (-6)^2 -4 * 1 * (-16)
∆= 36 + 64
∆ = 100

Aplicando na fórmula resolutiva:

x= -( b ± ✓∆) / 2a
x= (- (-6) ± ✓ 100) / 2 * 1
x = (6 ± 10) /2

x1 = (6 + 10) /2
x1 = 8

x2= (6 - 10) /2
x2= -2