Question

x²- 6 × + 9 = 0 usando a formula de bhaskara

Answer 1

x²-6+9=0     a= 1 b= (-6) e c = 9
b²-4*a*c
(-6)²-4*1*9
36-36
delta = 0

-b+ou - raiz de 0
----------------------
          2a
6+ou- 0
---------
2a

6+0
----- =   x1= 3 
2*1

6-0
----  =      x2= 3 
2*1

Answer 2

x² - 6x + 9 = 0

a = 1
b = - 6
c = 9

Δ = b² - 4 * a * c
Δ = ( - 6 ) ² - 4 * 1 * 9
Δ = 36 - 4 * 9
Δ = 36 - 36

$X= \frac{-b \frac{+}{} \sqrt{Delta} }{2*a} \\ \\ X= \frac{-(-6) \frac{+}{} \sqrt{0} }{2*1} \\ \\ X'= \frac{6+0}{2} =\ \textgreater \ \frac{6}{2}=\ \textgreater \ 3 \\ \\ X''= \frac{6-0}{2}=\ \textgreater \ \frac{6}{2}=\ \textgreater \ 3$= 0

- Espero Ter Ajudado E Bons Estudos !!