Question

x2 - 5x + 6 = 0 qual a resolução ​?

Answer 1

x² - 5x + 6 = 0

A= 1

B= - 5

C= 6

∆= b² - 4ac

∆= ( - 5)² - 4 • 1 • 6

∆= 25 - 24

∆= 1

x= - b ± √∆/2a

x= - ( - 5) ± √1 /2 • 1

x= 5 ± 1 / 2

x'= 5 + 1/2 = 6/2 = 3

x''= 5 - 1/2 = 4/2 = 2

S= ( 2 , 3)

Answer 2

${x}^{2} - 5x + 6 = 0 \\ \\ a = 1 \\ b = ( - 5) \\ c = 6 \\ \\ \Delta = {b}^{2} - 4ac \\ \Delta = {( - 5)}^{2} - 4 \times 1 \times 6 \\ \Delta =25 - 24 \\ \Delta = 1 \\ \\ x = \frac{ - b \pm \sqrt{ \Delta} }{2a} \\ \\ x = \frac{ - ( - 5) \pm \sqrt{1} }{2 \times 1} \\ \\ x = \frac{5 \pm1 }{2} \\ \\ x_{1} = \frac{5 + 1}{2} = \frac{6}{2} = 3\\ \\ x _{2} = \frac{5 - 1}{2} = \frac{4}{2} = 2$

S = {2, 3}