Question

X² -5X+6=0

Como faz?

Answer 1

$x^{2}-5x+6=0$

$a=1\\b=(-5)\\c=6$

$\Delta=b^{2} -4ac\\\Delta=(-5)^{2}-4\times1\times6\\\Delta=25-24\\\Delta=1$

$x=\frac{-b\pm\sqrt{\Delta} }{2a} \\\\x=\frac{-(-5)\pm\sqrt{1} }{2\times1} \\\\x=\frac{5\pm1}{2}$

$x_{1} =\frac{5+1}{2} =\frac{6}{2} =3\\\\x_{2} =\frac{5-1}{2} =\frac{4}{2} =2$

S = {2, 3}