Question

x²-5x+4=0
alguem me ajuda pfv? ​

Answer 1

x² - 5x + 4 = 0

Δ = (-5)² - 4.1.4

Δ = 25 - 16

Δ = 9

$x = \frac{-(-5)+-\sqrt{9} }{2.1}$

$x=\frac{5+-3}{2}$

$x^{1} = \frac{5-3}{2} \\x^{2} = \frac{5+3}{2}$

$x^{1} = 1\\x^{2} = 4$