Question

x²+5.x+y²-6.y+1 quando x=3 e y =0​

Answer 1

Oie, Td Bom?!

$= x {}^{2} + 5x + y {}^{2} - 6y + 1$

$= 3 {}^{2} + 5 \: . \: 3 + 0 {}^{2} - 6 \: . \: 0 + 1$

$= 9 + 15 + 0 - 0 + 1$

$= 9 + 15 + 1$

$= 10 + 15$

$= 25$

Att. Makaveli1996

Answer 2

$\sf {x}^{2} + 5 x + {y}^{2} - 6 y + 1$

$\sf = {3}^{2} + 5\cdot 3 + {0}^{2} - 6\cdot 0 + 1$

$\sf = 9 + 5\cdot 3 + 0 - 6\cdot 0 + 1$

$\sf = 9 +15 + 0 + 0 + 1$

$\sf = 9 +15 + 1$

$\sf = 10 +15$

$\red{\sf = 25}$