Question

x²-4x+3=0
prfv me ajude ​

Answer 1

Bom Dia !!!

$x^{2} - 4x + 3 = 0\\\\Resolverei\ por\ bhaskara\\\\a = 1\\\\b = -4\\\\c = 3\\\\\Delta = b^2 - 4.a.c\\\\\Delta = (-4)^2 - 4.1.3\\\\\Delta = 16 - 12\\\\\Delta = 4\\\\x = \frac{-b\pm\sqrt{\Delta} }{2.a} \\\\x = \frac{4 \pm2}{2} \\\\x' = \frac{6}{2} = 3\\\\x" = \frac{2}{2} = 1\\\\s = [3, 1]$

Espero ter ajudado :-)

Att: LDC