Question

– x² + 49x – 18 = 0

Answer 1

- x² + 49x - 18 = 0

delta = b² - 4ac

delta = 49² - 4 . (-1) . (-18)

delta = 2401 - 72

delta = 2 329

x = ( - b +- raiz de delta ) / 2a

x = ( - 49 +- raiz de 2 329 ) / 2.(-1)

x = ( - 49 +- 48,25 ) / - 2

x' = ( - 49 - 48,25 ) / - 2 = - 97,25 / - 2 = 48,625

x" = ( - 49 + 48,25 ) / - 2 = - 0,75 / - 2 = 0,375