Question

x²-49=0 com formula de delta e bhaskara

Answer 1

∆=0²-4.1.-49
∆=196

-0±√196/2.1

x= +14/2. 7
x= -14/2. -7

S={-7,7}

Answer 2

Bom dia!

equação:

$x^{2}-49= 0$

coeficientes:

a= 1, b= 0, c= -49

delta:

$\Delta = 0^{2}-4.1.(-49) \\ \Delta = 0-(-196) \\ \Delta = 196$

bhaskara (raízes):

$x= \frac{0 \pm \sqrt{196}}{2.1} \\ \\ x= \frac{0 \pm 14}{2} \\ \\ x'= \frac{0+14}{2}= \frac{14}{2}= 7 \\ \\ x''= \frac{0-14}{2}= -\frac{14}{2}= -7 \\ \\ \\ \boxed{S= (-7,7)}$