Question

x2-4/5x=1/5 . Como resolve isso ?

Answer 1

$x^{2} - \frac{4}{5x}- \frac{1}{5}=0 5 x^{2} -4x-1=0  -formula de bashara x^{2} = b^{2} -4(ac)=(-4)2 -4.5(-1)=36 x=6 x^{1}= \frac{b}{2a}= \frac{4}{10}+ \frac{6}{10} =1 x^{2} = \frac{b}{2a}= \frac{4}{10} - \frac{6}{10} = \frac{-1}{5}$

acho que e isso