Question

x²-3x-40=0 soluciona ai por favor 25 pts

Answer 1

$x^{2}-3x-40=0$

a=1 // b = -3 // c = -40

.

$delta = b^{2} - 4ac$

$delta = (-3)^{2} - 4(1)(-40)$

$delta = 9 + 160$

$delta = 169$

.

$x = \frac{(-b)+-\sqrt{delta}}{2a}$

$x = \frac{-(-3)+-\sqrt{169}}{2(1)}$

$x = \frac{3+-13}{2}$

.

$x'=\frac{3+13}{2}=\frac{16}{2}=8$

$x''=\frac{3-13}{2}=\frac{-10}{2}=-5$

.

x' = 8

x'' = -5

Answer 2

x²-3x-40=0
a=1 . b= -3 .c= 40
Delta= b ²2- 4ac
delta=(-3)²-4.1.(-40)
delta= 9+160
delta=169
x= -b-/+ raiz de delta/ 2a
x=-(-3)-13/2.1
x=3-13/2
x=10/2
x=-5
x=(-3)+13/2
x=16/2
x=8
S={(5,8)}