Question

x²+3x-10=0??????????????

Answer 1

x² + 3x - 10 = 0

a = 1; b = 3; c = -10

x = [- b ± √(b² - 4ac)] / 2a
x = [- 3 ± √(3² - 4 · 1 · [-10])] / 2 · 1
x = [- 3 ± √(9 + 40)] / 2
x = [- 3 ± √49] / 2
x = [- 3 ± 7] / 2
x' = [- 3 + 7] / 2 = 4 / 2 = 2
x'' = [- 3 - 7] / 2 = -10 / 2 = -5

S = [-5, 2]

Espero ter ajudado. Valeu!

Answer 2

x² + 3x - 10 = 0

Δ = b²−4ac
Δ = (3)²−4⋅1⋅(−10)
Δ = 9+40
Δ = 49


x = -b ± √Δ / 2a
x = -3 ± √49 / 2.1
x' = -3 - 7 / 2
x' = -10 / 2
x' = -5

x'' = -3 + 7 / 2
x'' = 4 / 2
x'' = 2

S = {-5, 2}