Question

x²-3.x+2=0
determine o valor de x¹ e x²​

Answer 1

Resposta:

Explicação passo-a-passo:

$\sf x^2-3x+2=0$

$\sf \Delta=(-3)^2-4\cdot1\cdot2$

$\sf \Delta=9-8$

$\sf \Delta=1$

$\sf x=\dfrac{-(-3)\pm\sqrt{1}}{2\cdot1}=\dfrac{3\pm1}{2}$

$\sf x_1=\dfrac{3+1}{2}~\rightarrow~x_1=\dfrac{4}{2}~\rightarrow~\red{x_1=2}$

$\sf x_2=\dfrac{3-1}{2}~\rightarrow~x_2=\dfrac{2}{2}~\rightarrow~\red{x_2=1}$