Question

x²-3√3x+6=0 Resolver em forma de delta e baskara!​

Answer 1

Explicação passo-a-passo:

• x²—3√3x+6=0

• Coeficientes:
• a=1
• b=—3√3
• c=6

• Discriminante:
• ∆ = b²—4•a•c
• $\Delta=(-3\sqrt{3})^{2}-4.1.6$
• ∆=9•3—24
• ∆ = 27—24
• ∆ = 3

• Bhaskara:
• $\boxed{\begin{array}{Ir}x_{1,2}=\frac{-b\pm\sqrt {\Delta}}{2.a}\end{array}}$
• $x_{1}=\frac{3\sqrt{3}-\sqrt{3}}{2}=\frac{(3-1)\sqrt{3}}{2}=\frac{2\sqrt{3}}{2}=\sqrt{3}$
• $x_{2}=\frac{3\sqrt{3}+\sqrt{3}}{2}=\frac{(3+1)\sqrt{3}}{2}=2\sqrt{3}$