Question

X²+2x-5=0 me ajudem a calcular a fórmula de baskara.

Answer 1

x^2+2x-5=0

b^2-4.ac

D= 2^2-4.1.-5
D=4+20=/24

-b+-/raizD÷2.a

X1=-2+24/2=22/2=11
X2=-2-24/2=-13

Answer 2

Oi Evelyne :)

x²+2x-5=0

a=1  ,  b=2   , c=-5

Δ = b² - 4.a.c 
Δ = 2² - 4 . 1 . -5 
Δ = 4 +20
Δ = 24

$x= \frac{-b+- \sqrt{\Delta} }{2a} \\ \\ x= \frac{-2+- \sqrt{24} }{2.1} \\ \\ x= \frac{-2+- 2\sqrt{6} }{2} \\ \\ x'= \frac{-2+ \sqrt{6} }{2} \ \ \ \ \ x''= \frac{-2-2 \sqrt{6} }{2} \\ \\ x'= \frac{-2}{2}+ \frac{2 \sqrt{6} }{2} \ \ \ \ \ x''= \frac{-2}{2}- \frac{2 \sqrt{6} }{2} \\ \\ \boxed{x'=-1+ \sqrt{6}} \ \ \ \ \ \boxed{x''=-1- \sqrt{6} }$

Foi realizada essa divisão:

$\boxed{ \frac{a+b}{c} = \frac{a}{c} + \frac{b}{c} }$


Espero que goste :)