Question

X2+2X-3=0 cálculo e resposta

Answer 1

x²+2x-3=0
∆=b²-4ac
∆=2²-4.1.(-3)
∆=4+12
∆=16
x=-b±√∆/2a
x=-2-4/2.1
x=-6/2
x=-3
x=-2+4/2.1
x=2/2
x=1
S={(-3 ; 1)}

Answer 2

x² + 2x - 3 = 0
a = 1     b = 2     c = -3

Delta = b² - 4ac
Delta = 4 - 4(1)(-3)
Delta = 4 + 12
Delta = 16

X = (-b +- raiz delta) / 2a
X = (-2 +- 4) / 2

x' = 2 / 2 = 1
x" = -6 / 2 = -3

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