Question

X²+2x_15=0 calcule o Bhaskara

Answer 1

$\large\boxed{\begin{array}{l} \rm \: x {}^{2} + 2x - 15 = 0 \\ \\\Rightarrow \begin{cases} \rm \: a = 1 \\ \rm \: b = 2 \\ \rm \: c = - 15\end{cases} \\ \\ \rm\Delta = b {}^{2} - 4ac \\\Delta = 2 {}^{2} - 4 \: . \: 1 \: . \: ( - 15) \\ \Delta = 4 + 60 \\\Delta = 64 \\ \\ \rm \: x = \dfrac{ - b \pm \sqrt{\Delta} }{2a} \\ \\ \rm \: x = \dfrac{ - 2 \pm \sqrt{64} }{2.1} \\ \\ \rm \: x = \dfrac{ - 2 \pm8}{2} \begin{cases} \rm \: x_1 = \dfrac{ - 2 + 8}{2} = \dfrac{6}{2} = \boxed{3} \\ \\ \rm \: x_2 = \dfrac{ - 2 - 8}{2} = \dfrac{ - 10}{2} = \boxed{ - 5} \end{cases}\end{array}}$

Answer 2

x²+2x-15=0

a=1

b=2

c=-15

∆=b²-4ac

∆=2²-4*1*-15

∆=4+60

∆=>64