Question

x²-2x+1=0 alguem sabe ???

Answer 1

x² - 2x + 1 = 0

Coeficientes: a = 1, b = -2 e c = 1

Δ = b² -4ac
Δ = (-2)² - 4 . 1 . 1
Δ = 4 - 4 . 1 . 1
Δ = 4 - 4
Δ = 0

x = (-b +- √Δ)/(2a)
x = (-(-2) +- √0)/(2.1)
x = 2/2 = 1



Espero ter ajudado.
Bons estudos!  : )

Answer 2

$\mathtt{x\²-2x+1=0 } \\ \\ \mathtt{a = 1} \\ \mathtt{b = -2} \\ \mathtt{c = 1} \\ \\ \mathtt{\Delta = b^2 -4 \times a \times c} \\ \\ \mathtt{\Delta =(-2)^2 -4 \times 1 \times 1 } \\ \mathtt{\Delta = 4 -4} \\ \mathtt{\Delta = 0} \\ \\ \mathtt{Por~\Delta = 0,~existe~apenas~uma~solu\c{c}\~ao} \\ \\ \mathtt{\frac{-b +-\sqrt{\Delta}} {2 \times a}} \\ \\ \mathtt{ \frac{-(-2) +-0}{2 \times 1} } \\ \\ \mathtt{x' = \frac{2}{2} } \\ \\ \mathtt{\underline{x' = 1}} \\ \\ \\ \boxed{\boxed{\mathtt{Resposta : x = 1}}}$