x²-20x+100=?
x²-8x+16
Soluções para a tarefa
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(I)
delta= bˆ2 - 4ac
delta=20ˆ2 -4.1.100
delta= 400-400
delta =0
x1= -(-20) + 0/2
x1=20+0/2
x1=20/2
x1=10
x2=20-0/2
x2=10
(II)
delta= 64-64
delta=0
x1= 8 + 0/2
x1=4
x2=4
delta= bˆ2 - 4ac
delta=20ˆ2 -4.1.100
delta= 400-400
delta =0
x1= -(-20) + 0/2
x1=20+0/2
x1=20/2
x1=10
x2=20-0/2
x2=10
(II)
delta= 64-64
delta=0
x1= 8 + 0/2
x1=4
x2=4
ismael12345:
Nossa me desculpa tentei facilitar mais piorei ainda mais
(I)
delta= bˆ2 - 4ac
delta=20ˆ2 -4.1.100
delta= 400-400
delta =0
x1= -(-20) + 0/2
x1=20+0/2
x1=20/2
x1=10
x2=20-0/2
x2=10
(II)
delta= 64-64
delta=0
x1= 8 + 0/2
x1=4
x2=4
delta= bˆ2 - 4ac
delta=20ˆ2 -4.1.100
delta= 400-400
delta =0
x1= -(-20) + 0/2
x1=20+0/2
x1=20/2
x1=10
x2=20-0/2
x2=10
(II)
delta= 64-64
delta=0
x1= 8 + 0/2
x1=4
x2=4
obrigada<3
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