Question

x2-20×+19=0
me ajudem nessa equação pfvr.​

Answer 1

Resposta:

$x^{2} -20x+19=0\\ \\ coeficientes:~a=1,~b=-20,~c=19\\ \\ delta=b^{2} -4.a.c\\ \\ delta=(-20)^{2} -4.1.19\\ \\ delta=400-76\\ \\ delta=324$

$x=\frac{-b+-\sqrt{delta} }{2.a} \\ \\ x=\frac{-(-20)+-\sqrt{324} }{2} \\ \\ x=\frac{20+-18}{2} \\ \\ x'=\frac{20-18}{2} =\frac{2}{2} =1\\ \\ x''=\frac{20+18}{2} =\frac{38}{2} =19\\ \\ \\ S~~~~\left \{ {{1,~~19} {}} \}$