Question

x² + 18x + 4 = -8 resolvam pfv

Answer 1

x²+18x+4=-8
x²+18x+4+8=0
x²+18x+12=0

a=1
b=18
c=12

$x= \frac{-b+- \sqrt{b^{2}-4ac } }{2a} \\ \\ x= \frac{-18+- \sqrt{(18)^{2}-4*1*12 } }{2*1} \\ \\ x= \frac{-18+- \sqrt{324-4*12} }{2} \\ \\ x= \frac{-18+- \sqrt{324-48} }{2} \\ \\ x= \frac{-18+- \sqrt{276} }{2} \\ \\ x= \frac{-18+- \sqrt{2^{2}*69 } }{2} \\ \\ x= \frac{-18+-2 \sqrt{69} }{2} \\ \\ x= \frac{-18}{2} +- \frac{2 \sqrt{69} }{2} \\ \\ x= \frac{-18}{2} +- \sqrt{69} \\ \\ x=-9+- \sqrt{69} \\ \\ \\ \left \{ {{x=-9+ \sqrt{69} } \atop {x=-9- \sqrt{69} }} \right.$

Espero ter ajudado