Question

x²+18×+81= quero resposta​

Answer 1

Explicação passo-a-passo:

$x^2 +18x+81 = 0\\x = \frac{-b+-\sqrt{b^2-4ac} }{2a} \\x = \frac{-18+-\sqrt{18^2-4.1.81} }{2.1} \\x = \frac{-18+-\sqrt{324-324} }{2} \\x = \frac{-18+-\sqrt{0} }{2} \\x = \frac{-18+-0 }{2} \\\\x = \frac{-18 }{2} \\\\\\\\x = -9$