Question

=-x²+13x-4=0 

 

Answer 1

$- x^{2} +13x-4=0 \Delta= b^{2} -4.a.c= \Delta= 13^{2} -4.(-1).(-4)= \Delta=169-16=153 x^{1} =-+13 \sqrt{153} /2=13- \sqrt{153} /2  x^{2} =-+13 \sqrt{153} /2=13+ \sqrt{153} /2$